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A simple math puzzle game that teaches basic arithmetic, like addition and subtraction. Numbers grow and change in difficulty as the player goes on.
For equation solving, Wolfram|Alpha calls the Wolfram Language's Solve and Reduce functions, which contain a broad range of methods for all kinds of algebra, from basic linear and quadratic equations to multivariate nonlinear systems. In some cases, linear algebra methods such as Gaussian elimination are used, with optimizations to increase speed and reliability. Other operations rely on theorems and algorithms from number theory, abstract algebra and other advanced fields to compute results. These methods are carefully designed and chosen to enable Wolfram|Alpha to solve the greatest variety of problems while also minimizing computation time. In some cases, the numbers worked with are so large that special notations such as Knuth's up-arrow notation, the Conway chained arrow notation, and Steinhaus-Moser notation were conceived. Nevertheless, there are certainly scientific uses for big number calculators today, and even if a person may not have any need to use one, it can certainly be entertaining to satiate one's curiosity of what 10,000 factorial looks like on a screen.
The percentage increase calculator above computes an increase or decrease of a specific percentage of the input number. It basically involves converting a percent into its decimal equivalent, and either subtracting (decrease) or adding (increase) the decimal equivalent from and to 1, respectively. Multiplying the original number by this value will result in either an increase or decrease of the number by the given percent. Refer to the example below for clarification.Two solutions that have the same molarity will have the same number of molecules of the chemical per liter but are likely to contain differing masses of that chemical per liter to achieve this. Whereas two solutions at the same concentration will have the same mass of the chemical per liter of solution but are therefore likely to have differing numbers of molecules of that chemical per liter. Provided some additional information is known, one value can be deduced from the other using the equations below. (Source: www.technologynetworks.com)