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How to Figure Fractions

Fractions are made up of integers. This means that the number 1/2 is equivalent to the number {1 x 1/2}. Fractions are also commensurable: if you add 3/2 and 8/2 together, you have {3 + 8/2}. In this article, we will cover how fractions are made, how to perform calculations with fractions, and some of the purposes these calculations serve.

We know that, 9/18=27/? Here, the numerators of the two fractions are 9 and 27 respectively. Now, we have to find a number, which, when multiplied by 9 gives 27. We know that 9 × 3 = 27. Hence, we multiply the numerator and the denominator of the given fraction by 3 =\(\dfrac{9 \times 3}{18 \times 3}\)= 27/54. Therefore, the denominator of the equivalent fraction of 9/18 is 54. To check if the given fractions are equivalent, we will make the denominators the same by multiplication. The denominators of the fractions 12/20 and 22/30 are 20 and 30. The LCM of the denominators is 60. Let us make the denominators of both the fractions equal to 60, by multiplying them with the suitable numbers: 12/20=\(\dfrac{12 \times 3}{20 \times 3}\)= 36/60, 22/30=\(\dfrac{22 \times 2}{30 \times 2}\)= 44/60. Here, it can be seen that 36 is not equal to 44, that is 36 < 44. Therefore, 12/20 and 22/30 are not equivalent fractions.

We need to simplify the given fractions to find whether they are equivalent or not. Simplification to get equivalent numbers can be done to a point where both the numerator and denominator should still be whole numbers. There are various methods to identify if the given fractions are equivalent. Some of them are:To find the equivalent fractions for any given fraction, divide the numerator and the denominator by the same number. For example, to find an equivalent fraction of 72/108, we will first find their common factors. We know that 2 is a common factor of both 72 and 108. Hence, an equivalent fraction of 72/108 can be found by dividing its numerator and denominator by 2. Thus, 36/54 is an equivalent fraction of 72/108. Let us see how the fraction is further simplified: (Source: www.cuemath.com)